3.5.94 \(\int (d-c^2 d x^2)^{5/2} (a+b \text {ArcSin}(c x))^n \, dx\) [494]

Optimal. Leaf size=698 \[ \frac {5 d^2 \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^{1+n}}{16 b c (1+n) \sqrt {1-c^2 x^2}}-\frac {15 i 2^{-7-n} d^2 e^{-\frac {2 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (-\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (1+n,-\frac {2 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {15 i 2^{-7-n} d^2 e^{\frac {2 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (1+n,\frac {2 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}-\frac {3 i 2^{-7-2 n} d^2 e^{-\frac {4 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (-\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (1+n,-\frac {4 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {3 i 2^{-7-2 n} d^2 e^{\frac {4 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (1+n,\frac {4 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}-\frac {i 2^{-7-n} 3^{-1-n} d^2 e^{-\frac {6 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (-\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (1+n,-\frac {6 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {i 2^{-7-n} 3^{-1-n} d^2 e^{\frac {6 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (1+n,\frac {6 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}} \]

[Out]

5/16*d^2*(a+b*arcsin(c*x))^(1+n)*(-c^2*d*x^2+d)^(1/2)/b/c/(1+n)/(-c^2*x^2+1)^(1/2)-15*I*2^(-7-n)*d^2*(a+b*arcs
in(c*x))^n*GAMMA(1+n,-2*I*(a+b*arcsin(c*x))/b)*(-c^2*d*x^2+d)^(1/2)/c/exp(2*I*a/b)/((-I*(a+b*arcsin(c*x))/b)^n
)/(-c^2*x^2+1)^(1/2)+15*I*2^(-7-n)*d^2*exp(2*I*a/b)*(a+b*arcsin(c*x))^n*GAMMA(1+n,2*I*(a+b*arcsin(c*x))/b)*(-c
^2*d*x^2+d)^(1/2)/c/((I*(a+b*arcsin(c*x))/b)^n)/(-c^2*x^2+1)^(1/2)-3*I*2^(-7-2*n)*d^2*(a+b*arcsin(c*x))^n*GAMM
A(1+n,-4*I*(a+b*arcsin(c*x))/b)*(-c^2*d*x^2+d)^(1/2)/c/exp(4*I*a/b)/((-I*(a+b*arcsin(c*x))/b)^n)/(-c^2*x^2+1)^
(1/2)+3*I*2^(-7-2*n)*d^2*exp(4*I*a/b)*(a+b*arcsin(c*x))^n*GAMMA(1+n,4*I*(a+b*arcsin(c*x))/b)*(-c^2*d*x^2+d)^(1
/2)/c/((I*(a+b*arcsin(c*x))/b)^n)/(-c^2*x^2+1)^(1/2)-I*2^(-7-n)*3^(-1-n)*d^2*(a+b*arcsin(c*x))^n*GAMMA(1+n,-6*
I*(a+b*arcsin(c*x))/b)*(-c^2*d*x^2+d)^(1/2)/c/exp(6*I*a/b)/((-I*(a+b*arcsin(c*x))/b)^n)/(-c^2*x^2+1)^(1/2)+I*2
^(-7-n)*3^(-1-n)*d^2*exp(6*I*a/b)*(a+b*arcsin(c*x))^n*GAMMA(1+n,6*I*(a+b*arcsin(c*x))/b)*(-c^2*d*x^2+d)^(1/2)/
c/((I*(a+b*arcsin(c*x))/b)^n)/(-c^2*x^2+1)^(1/2)

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Rubi [A]
time = 0.35, antiderivative size = 698, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 4, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {4753, 3393, 3388, 2212} \begin {gather*} -\frac {15 i d^2 2^{-n-7} e^{-\frac {2 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (-\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (n+1,-\frac {2 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}-\frac {3 i d^2 2^{-2 n-7} e^{-\frac {4 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (-\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (n+1,-\frac {4 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}-\frac {i d^2 2^{-n-7} 3^{-n-1} e^{-\frac {6 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (-\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (n+1,-\frac {6 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {15 i d^2 2^{-n-7} e^{\frac {2 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (n+1,\frac {2 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {3 i d^2 2^{-2 n-7} e^{\frac {4 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (n+1,\frac {4 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {i d^2 2^{-n-7} 3^{-n-1} e^{\frac {6 i a}{b}} \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^n \left (\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (n+1,\frac {6 i (a+b \text {ArcSin}(c x))}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {5 d^2 \sqrt {d-c^2 d x^2} (a+b \text {ArcSin}(c x))^{n+1}}{16 b c (n+1) \sqrt {1-c^2 x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(d - c^2*d*x^2)^(5/2)*(a + b*ArcSin[c*x])^n,x]

[Out]

(5*d^2*Sqrt[d - c^2*d*x^2]*(a + b*ArcSin[c*x])^(1 + n))/(16*b*c*(1 + n)*Sqrt[1 - c^2*x^2]) - ((15*I)*2^(-7 - n
)*d^2*Sqrt[d - c^2*d*x^2]*(a + b*ArcSin[c*x])^n*Gamma[1 + n, ((-2*I)*(a + b*ArcSin[c*x]))/b])/(c*E^(((2*I)*a)/
b)*Sqrt[1 - c^2*x^2]*(((-I)*(a + b*ArcSin[c*x]))/b)^n) + ((15*I)*2^(-7 - n)*d^2*E^(((2*I)*a)/b)*Sqrt[d - c^2*d
*x^2]*(a + b*ArcSin[c*x])^n*Gamma[1 + n, ((2*I)*(a + b*ArcSin[c*x]))/b])/(c*Sqrt[1 - c^2*x^2]*((I*(a + b*ArcSi
n[c*x]))/b)^n) - ((3*I)*2^(-7 - 2*n)*d^2*Sqrt[d - c^2*d*x^2]*(a + b*ArcSin[c*x])^n*Gamma[1 + n, ((-4*I)*(a + b
*ArcSin[c*x]))/b])/(c*E^(((4*I)*a)/b)*Sqrt[1 - c^2*x^2]*(((-I)*(a + b*ArcSin[c*x]))/b)^n) + ((3*I)*2^(-7 - 2*n
)*d^2*E^(((4*I)*a)/b)*Sqrt[d - c^2*d*x^2]*(a + b*ArcSin[c*x])^n*Gamma[1 + n, ((4*I)*(a + b*ArcSin[c*x]))/b])/(
c*Sqrt[1 - c^2*x^2]*((I*(a + b*ArcSin[c*x]))/b)^n) - (I*2^(-7 - n)*3^(-1 - n)*d^2*Sqrt[d - c^2*d*x^2]*(a + b*A
rcSin[c*x])^n*Gamma[1 + n, ((-6*I)*(a + b*ArcSin[c*x]))/b])/(c*E^(((6*I)*a)/b)*Sqrt[1 - c^2*x^2]*(((-I)*(a + b
*ArcSin[c*x]))/b)^n) + (I*2^(-7 - n)*3^(-1 - n)*d^2*E^(((6*I)*a)/b)*Sqrt[d - c^2*d*x^2]*(a + b*ArcSin[c*x])^n*
Gamma[1 + n, ((6*I)*(a + b*ArcSin[c*x]))/b])/(c*Sqrt[1 - c^2*x^2]*((I*(a + b*ArcSin[c*x]))/b)^n)

Rule 2212

Int[(F_)^((g_.)*((e_.) + (f_.)*(x_)))*((c_.) + (d_.)*(x_))^(m_), x_Symbol] :> Simp[(-F^(g*(e - c*(f/d))))*((c
+ d*x)^FracPart[m]/(d*((-f)*g*(Log[F]/d))^(IntPart[m] + 1)*((-f)*g*Log[F]*((c + d*x)/d))^FracPart[m]))*Gamma[m
+ 1, ((-f)*g*(Log[F]/d))*(c + d*x)], x] /; FreeQ[{F, c, d, e, f, g, m}, x] &&  !IntegerQ[m]

Rule 3388

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + Pi*(k_.) + (f_.)*(x_)], x_Symbol] :> Dist[I/2, Int[(c + d*x)^m/(E^(
I*k*Pi)*E^(I*(e + f*x))), x], x] - Dist[I/2, Int[(c + d*x)^m*E^(I*k*Pi)*E^(I*(e + f*x)), x], x] /; FreeQ[{c, d
, e, f, m}, x] && IntegerQ[2*k]

Rule 3393

Int[((c_.) + (d_.)*(x_))^(m_)*sin[(e_.) + (f_.)*(x_)]^(n_), x_Symbol] :> Int[ExpandTrigReduce[(c + d*x)^m, Sin
[e + f*x]^n, x], x] /; FreeQ[{c, d, e, f, m}, x] && IGtQ[n, 1] && ( !RationalQ[m] || (GeQ[m, -1] && LtQ[m, 1])
)

Rule 4753

Int[((a_.) + ArcSin[(c_.)*(x_)]*(b_.))^(n_.)*((d_) + (e_.)*(x_)^2)^(p_.), x_Symbol] :> Dist[(1/(b*c))*Simp[(d
+ e*x^2)^p/(1 - c^2*x^2)^p], Subst[Int[x^n*Cos[-a/b + x/b]^(2*p + 1), x], x, a + b*ArcSin[c*x]], x] /; FreeQ[{
a, b, c, d, e, n}, x] && EqQ[c^2*d + e, 0] && IGtQ[2*p, 0]

Rubi steps

\begin {align*} \int \left (d-c^2 d x^2\right )^{5/2} \left (a+b \sin ^{-1}(c x)\right )^n \, dx &=\frac {\left (d^2 \sqrt {d-c^2 d x^2}\right ) \int \left (1-c^2 x^2\right )^{5/2} \left (a+b \sin ^{-1}(c x)\right )^n \, dx}{\sqrt {1-c^2 x^2}}\\ &=\frac {\left (d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int (a+b x)^n \cos ^6(x) \, dx,x,\sin ^{-1}(c x)\right )}{c \sqrt {1-c^2 x^2}}\\ &=\frac {\left (d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int \left (\frac {5}{16} (a+b x)^n+\frac {15}{32} (a+b x)^n \cos (2 x)+\frac {3}{16} (a+b x)^n \cos (4 x)+\frac {1}{32} (a+b x)^n \cos (6 x)\right ) \, dx,x,\sin ^{-1}(c x)\right )}{c \sqrt {1-c^2 x^2}}\\ &=\frac {5 d^2 \sqrt {d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^{1+n}}{16 b c (1+n) \sqrt {1-c^2 x^2}}+\frac {\left (d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int (a+b x)^n \cos (6 x) \, dx,x,\sin ^{-1}(c x)\right )}{32 c \sqrt {1-c^2 x^2}}+\frac {\left (3 d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int (a+b x)^n \cos (4 x) \, dx,x,\sin ^{-1}(c x)\right )}{16 c \sqrt {1-c^2 x^2}}+\frac {\left (15 d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int (a+b x)^n \cos (2 x) \, dx,x,\sin ^{-1}(c x)\right )}{32 c \sqrt {1-c^2 x^2}}\\ &=\frac {5 d^2 \sqrt {d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^{1+n}}{16 b c (1+n) \sqrt {1-c^2 x^2}}+\frac {\left (d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{-6 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{64 c \sqrt {1-c^2 x^2}}+\frac {\left (d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{6 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{64 c \sqrt {1-c^2 x^2}}+\frac {\left (3 d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{-4 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{32 c \sqrt {1-c^2 x^2}}+\frac {\left (3 d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{4 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{32 c \sqrt {1-c^2 x^2}}+\frac {\left (15 d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{-2 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{64 c \sqrt {1-c^2 x^2}}+\frac {\left (15 d^2 \sqrt {d-c^2 d x^2}\right ) \text {Subst}\left (\int e^{2 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{64 c \sqrt {1-c^2 x^2}}\\ &=\frac {5 d^2 \sqrt {d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^{1+n}}{16 b c (1+n) \sqrt {1-c^2 x^2}}-\frac {15 i 2^{-7-n} d^2 e^{-\frac {2 i a}{b}} \sqrt {d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac {i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,-\frac {2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {15 i 2^{-7-n} d^2 e^{\frac {2 i a}{b}} \sqrt {d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac {i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,\frac {2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt {1-c^2 x^2}}-\frac {3 i 2^{-7-2 n} d^2 e^{-\frac {4 i a}{b}} \sqrt {d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac {i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,-\frac {4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {3 i 2^{-7-2 n} d^2 e^{\frac {4 i a}{b}} \sqrt {d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac {i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,\frac {4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt {1-c^2 x^2}}-\frac {i 2^{-7-n} 3^{-1-n} d^2 e^{-\frac {6 i a}{b}} \sqrt {d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac {i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,-\frac {6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt {1-c^2 x^2}}+\frac {i 2^{-7-n} 3^{-1-n} d^2 e^{\frac {6 i a}{b}} \sqrt {d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac {i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,\frac {6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt {1-c^2 x^2}}\\ \end {align*}

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Mathematica [A]
time = 2.88, size = 477, normalized size = 0.68 \begin {gather*} \frac {d^3 \sqrt {1-c^2 x^2} (a+b \text {ArcSin}(c x))^n \left (\frac {120 a}{b+b n}+\frac {120 \text {ArcSin}(c x)}{1+n}-45 i 2^{-n} e^{-\frac {2 i a}{b}} \left (-\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (1+n,-\frac {2 i (a+b \text {ArcSin}(c x))}{b}\right )+45 i 2^{-n} e^{\frac {2 i a}{b}} \left (\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^{-n} \text {Gamma}\left (1+n,\frac {2 i (a+b \text {ArcSin}(c x))}{b}\right )-9 i 4^{-n} e^{-\frac {4 i a}{b}} \left (\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^n \left (\frac {(a+b \text {ArcSin}(c x))^2}{b^2}\right )^{-n} \text {Gamma}\left (1+n,-\frac {4 i (a+b \text {ArcSin}(c x))}{b}\right )+9 i 4^{-n} e^{\frac {4 i a}{b}} \left (-\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^n \left (\frac {(a+b \text {ArcSin}(c x))^2}{b^2}\right )^{-n} \text {Gamma}\left (1+n,\frac {4 i (a+b \text {ArcSin}(c x))}{b}\right )-i 6^{-n} e^{-\frac {6 i a}{b}} \left (\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^n \left (\frac {(a+b \text {ArcSin}(c x))^2}{b^2}\right )^{-n} \text {Gamma}\left (1+n,-\frac {6 i (a+b \text {ArcSin}(c x))}{b}\right )+i 6^{-n} e^{\frac {6 i a}{b}} \left (-\frac {i (a+b \text {ArcSin}(c x))}{b}\right )^n \left (\frac {(a+b \text {ArcSin}(c x))^2}{b^2}\right )^{-n} \text {Gamma}\left (1+n,\frac {6 i (a+b \text {ArcSin}(c x))}{b}\right )\right )}{384 c \sqrt {d-c^2 d x^2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(d - c^2*d*x^2)^(5/2)*(a + b*ArcSin[c*x])^n,x]

[Out]

(d^3*Sqrt[1 - c^2*x^2]*(a + b*ArcSin[c*x])^n*((120*a)/(b + b*n) + (120*ArcSin[c*x])/(1 + n) - ((45*I)*Gamma[1
+ n, ((-2*I)*(a + b*ArcSin[c*x]))/b])/(2^n*E^(((2*I)*a)/b)*(((-I)*(a + b*ArcSin[c*x]))/b)^n) + ((45*I)*E^(((2*
I)*a)/b)*Gamma[1 + n, ((2*I)*(a + b*ArcSin[c*x]))/b])/(2^n*((I*(a + b*ArcSin[c*x]))/b)^n) - ((9*I)*((I*(a + b*
ArcSin[c*x]))/b)^n*Gamma[1 + n, ((-4*I)*(a + b*ArcSin[c*x]))/b])/(4^n*E^(((4*I)*a)/b)*((a + b*ArcSin[c*x])^2/b
^2)^n) + ((9*I)*E^(((4*I)*a)/b)*(((-I)*(a + b*ArcSin[c*x]))/b)^n*Gamma[1 + n, ((4*I)*(a + b*ArcSin[c*x]))/b])/
(4^n*((a + b*ArcSin[c*x])^2/b^2)^n) - (I*((I*(a + b*ArcSin[c*x]))/b)^n*Gamma[1 + n, ((-6*I)*(a + b*ArcSin[c*x]
))/b])/(6^n*E^(((6*I)*a)/b)*((a + b*ArcSin[c*x])^2/b^2)^n) + (I*E^(((6*I)*a)/b)*(((-I)*(a + b*ArcSin[c*x]))/b)
^n*Gamma[1 + n, ((6*I)*(a + b*ArcSin[c*x]))/b])/(6^n*((a + b*ArcSin[c*x])^2/b^2)^n)))/(384*c*Sqrt[d - c^2*d*x^
2])

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Maple [F]
time = 0.11, size = 0, normalized size = 0.00 \[\int \left (-c^{2} d \,x^{2}+d \right )^{\frac {5}{2}} \left (a +b \arcsin \left (c x \right )\right )^{n}\, dx\]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((-c^2*d*x^2+d)^(5/2)*(a+b*arcsin(c*x))^n,x)

[Out]

int((-c^2*d*x^2+d)^(5/2)*(a+b*arcsin(c*x))^n,x)

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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-c^2*d*x^2+d)^(5/2)*(a+b*arcsin(c*x))^n,x, algorithm="maxima")

[Out]

integrate((-c^2*d*x^2 + d)^(5/2)*(b*arcsin(c*x) + a)^n, x)

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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-c^2*d*x^2+d)^(5/2)*(a+b*arcsin(c*x))^n,x, algorithm="fricas")

[Out]

integral((c^4*d^2*x^4 - 2*c^2*d^2*x^2 + d^2)*sqrt(-c^2*d*x^2 + d)*(b*arcsin(c*x) + a)^n, x)

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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: SystemError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-c**2*d*x**2+d)**(5/2)*(a+b*asin(c*x))**n,x)

[Out]

Exception raised: SystemError >> excessive stack use: stack is 6189 deep

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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((-c^2*d*x^2+d)^(5/2)*(a+b*arcsin(c*x))^n,x, algorithm="giac")

[Out]

Exception raised: TypeError >> An error occurred running a Giac command:INPUT:sage2:=int(sage0,sageVARx):;OUTP
UT:sym2poly/r2sym(const gen & e,const index_m & i,const vecteur & l) Error: Bad Argument Value

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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (a+b\,\mathrm {asin}\left (c\,x\right )\right )}^n\,{\left (d-c^2\,d\,x^2\right )}^{5/2} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*asin(c*x))^n*(d - c^2*d*x^2)^(5/2),x)

[Out]

int((a + b*asin(c*x))^n*(d - c^2*d*x^2)^(5/2), x)

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